y^2-5y+25/4=0

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Solution for y^2-5y+25/4=0 equation: 



y^2-5y+25/4=0

We multiply all the terms by the denominator


y^2*4-5y*4+25=0

Wy multiply elements

4y^2-20y+25=0

a = 4; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{20}{8}=2+1/2$

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